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Showing 1 - 10 of 90 results
  • Updated 17 months ago
    These diagrams are helpful because they allow us to predict the shape of the molecule and see the positions of each atom relative to the others. In the case of CO 2 , when it comes time to create a lewis structure, it seems as though you don not have enough electrons to complete the octets of all the atoms. If you go about the steps that were given to you above, you will notice that the octets of the oxygen atoms have been filled, but the carbon still needs 4 more electrons.
  • Updated 17 months ago
    During the light reactions, energy from light is used to make ATP and NADPH, which are used to provide energy for the making of glucose, for exmple. Chlorophyll: Chlorophyll is a pigment that absorbs light in the blue and red wavelengths, which appears green to our eyes.The primary types are chlorophyll a and chlorophyll b. Thylakoid membranes: This is where the chlorophyll, which are carriers for electron transport and are the required components for synthesis of ATP and NADPH, are stored.
  • Updated 17 months ago
    Where Y is the absolute yield, N is the number of atoms a given nucleus formed, and P is the number of fission events. The fissile material is encased in a solid cladding, made of Zircalloy, to contain both the fuel and the resulting fission products and keep then from escaping into the moderator, coolant, or anywhere outside the cladding.
  • Updated 17 months ago
    The electronic-state configurations for molecules can be described by the primary quantum number n, the angular momentum quantum number Λ, the spin quantum number S, which remains a good quantum number, the quantum number Σ (S, S-1, ..., -S), and the projection of the total angular momentum quantum number onto the molecular symmetry axis Ω, which can be derived as Ω=Λ+Σ.
  • Updated 17 months ago
    Through a careful study of multiple model compounds of known oxidation states and spin configurations, from Ni(I), to low- and high-spin Ni(III) up to Ni(IV), a relationship is derived between the position of the L 3 edge and the ratio of the integrals of the L 3 and L 2 edges.
  • Updated 17 months ago
    This rule states that the absorption coefficient is proportional to the square of the transition moment integral, or |<i|H|f>| 2 , where i is the unaffected core energy level before it interferes with the neighboring atoms, H is the interaction, and f is the final state in which the core energy level has been affected and a photoelectron has been ejected.
  • Updated 17 months ago
    In order to observe resonance, the frequency of the microwaves must correspond to the splitting of the spin states of the electron, which is determined by the strength of the magnetic field. The peaks seen in figure 12 correspond to specific quantitative parameters that describe the coupling of the electron and the nucleus, thus corresponding to the distance between the nuclei and the electron.
  • Updated 17 months ago
    To determine this, we take the equation from the aforementioned Simple Cubic unit cell and add to the parenthesized six faces of the unit cell multiplied by one-half (due to the lattice points on each face of the cubic cell). Next we find the mass of the unit cell by multiplying the number of atoms in the unit cell by the mass of each atom (1.79 x 10 -22 g/atom)(4) = 7.167 x 10 -22 grams.
  • Updated 14 months ago
    The somewhat less common MLCT has the same intensity and energy of the LMCT as they involve the transition of an electron from the t2g (pi) and the eg (sigma*) to the t1u (pi*/sigma*). In addition, the d-d transitions are lower in energy than the CT band because of the smaller energy gap between the t2g and eg in octahedral complexes (or eg to t2g in tetrahedral complexes) than the energy gap between the ground and excited states of the charge transfer band.
  • Updated 17 months ago
    Cut the sodium to approximately the appropriate size while there is still a small amount of oil remaining on the metal. Finely powdered sodium metal should never be handled in the open as exposure to moisture will both reduce the quality of the reagent as well as potentially cause large fires which are difficult to extinguish. To extinguish a metal fire, it is ideal to either use an appropriate Metal "Class D" fire extinguisher or to pour large quantities of SAND over the fire.
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