Accuracy and precision are very important in chemistry. However, the laboratory equipments and machines used in labs are limited in such a way that they can only determine a certain amount of data. For example, a scale can only mass an object up until a certain decimal place, because no machine is advanced enough to determine an infinite amount of digits. Machines are only able to determine a certain amount of digits precisely. These numbers that are determined precisely are called significant digits. Thus, a scale that could only mass until 99.999 mg, could only measure up to 5 figures of accuracy (5 significant digits). Furthermore, in order to have accurate calculations, the end calculation should not have more significant digits than the original set of data.
Significant Digits - Number of digits in a figure that express the precision of a measurement instead of its magnitude. The easiest method to determine significant digits is done by first determining whether or not a number has a decimal point. This rule is known as the Atlantic-Pacific Rule. The rule states that if a decimal point is Absent, then the zeroes on the Atlantic/right side are insignificant. If a decimal point is Present, then the zeroes on the Pacific/left side are insignificant.
Ex) The first two zeroes in 200500 (four significant digits) are significantbecause they are between two non-zero digits, and the last two zeroes are insignificant because they are after the last non-zero digit.
It should be noted that both constants and quantities of real world objects have an infinite number of significant figures. For example if you were to count three oranges, a real world object, the value three would be considered to have an infinite number of significant figures in this context.
How many significant digits are in 5010?
5 0 1 0 Key: 0 = significant zero. 0 = insignificant zero.
Answer: 3 significant digits.
Ex) The first two zeroes in 0.058000 (five significant digits) are insignificant because they are before the first non-zero digit, and the last three zeroes are significant because they are after the first non-zero digit.
How many significant digits are in 0.70620?
0 . 7 0 6 2 0 Key: 0 = significant zero.0 = insignificant zero.
Answer: 5 significant digits.
Scientific notation form: a x 10b, where “a” and “b” are integers, and "a" has to be between 1 and 10.
How many significant digits are in 1.52 x 106?
NOTE: Only determine the amount of significant digits in the "1.52" part of the scientific notation form.
Answer: 3 significant digits.
When rounding numbers to a significant digit, keep the amount of significant digits wished to be kept, and replace the other numbers with insignificant zeroes. The reason for rounding a number to a particular amount of significant digits is because in a calculation, some values have less significant digits than other values, and the answer to a calculation is only accurate to the amount of significant digits of the value with the least amount. NOTE: be careful when rounding numbers with a decimal point. Any zeroes added after the first non-zero digit is considered to be a significant zero. TIP: When doing calculations for quizzes/tests/midterms/finals, it would be best to not round in the middle of your calculations, and round to the significant digit only at the end of your calculations.
Round 32445.34 to 2 significant digits.
Answer: 32000 (NOT 32000.00, which has 7 significant digits. Due to the decimal point, the zeroes after the first non-zero digit become significant).
When adding or subtracting numbers, the end result should have the same amount of decimal places as the number with the least amount of decimal places.
Y = 232.234 + 0.27 Find Y.
Answer: Y = 232.50
NOTE: 232.234 has 3 decimal places and 0.27 has 2 decimal places. The least amount of decimal places is 2. Thus, the answer must be rounded to the 2nd decimal place (thousandth).
When multiplying or dividing numbers, the end result should have the same amount of significant digits as the number with the least amount of significant digits.
Y = 28 x 47.3 Find Y
Answer: Y = 1300
NOTE: 28 has 2 significant digits and 47.3 has 3 significant digits. The least amount of significant digits is 2. Thus, the answer must me rounded to 2 significant digits (which is done by keeping 2 significant digits and replacing the rest of the digits with insignificant zeroes).
Exact numbers can be considered to have an unlimited number of significant figures, as such calculations are not subject to errors in measurement. This may occur:
1. a) How many significant digits Are in 50?
b) How many significant digits Are in 50.?
2. How many significant digits Are in 3.670 x 1035?
3. Round 4279852.243 to 3 significant digits.
4. Round 0.0573000 to 1 significant digit.
5. Y = 45.2 + 16.730 Find Y.
6. Y = 23 – 26.2 Find Y.
7. Y = 16.7 x 33.2 x 16.72 Find Y.
8. Y = 346 ÷ 22 Find Y.
9. Y = (23.2 + 16.723) x 28 Find Y
10. Y = (16.7 x 23) – (23.2 ÷ 2.13) Find Y
Solutions to Additional Problems
1. a) 1 significant digit.
b) 2 significant digits.
2. 4 significant digits.
5. Y = 61.9
6. Y = -3
7. Y = 9270
8. Y = 16
9. Y = (23.2 + 16.723) x 28
Y = 39.923 x 28 TIP: Do not round until the end of calculations.
Y = 1100 NOTE: 28 has the least amount of significant digits (2 sig. figs.) Thus, answer must be rounded to 2 sig. figs.
10. Y = (16.7 x 23) – (23.2 ÷ 2.13)
Y = 384.1 – 10.89201878 TIP: Do not round until the end of calculations.
Y = 373.2 NOTE: 384.1 has the least amount of decimal point (tenth). Thus, answer must be rounded to the tenth.
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