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Degree of Unsaturation

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Yen Tran says:
hey! simple and straight to the point, but don't forget to mention that with the unsaturation of 4 or higher gives you a benzene ring. Also, instead of mentioning the number of degrees of unsaturation gives you a double bond or ring in a bullet form I think it would be helpful to draw a chart for that. It is easier to see and understand when things are drawn in a chart. Like Paul said, what is the degree of unsaturation meant? edited 11:11, 8 Mar 2009
Posted 02:09, 2 Mar 2009
Hey. This is good. Something that I thought of though was maybe to emphasis a little more exactly what degrees of unsaturation meant. You do a good job giving examples but maybe you could write out an formula or something. Also I remember being confused if a ring had a double bond in it how many degrees of unsaturation that was. Like Yen said you could maybe add an example of why benzene has four degrees of unsaturation.
Posted 23:28, 5 Mar 2009
Your module is very straightforward but I think it lacks explanation of the underlining concept of unsaturation.
You can find this information from our Ochem textbook and other websites too. Basically, the above equation is derived from the number of H required for the molecule to be saturated.
H(required for sat) = 2C + 2 - X + N
by subtracting H(sat) from both sides and divides by 2, you get the formula for the degree of unsaturation.
You should explain the reason why this equation makes sense. For example,
1/ we subtract X because the presence of 1 halogen means 1 less H is needed to attach to the C
2/ we add N because when nitrogen is present, more H is needed to bond to the N and keep the molecule saturated.
3/ O is ignored in the calculation because it has no effect on the number of H needed for saturation. Consider CH3CH2OH. if we eliminate the O, the molecule becomes CH3CH2-H, fully saturated. Thus O is irrelevant.
and so on...
While your module provides all information needed to calculate the degree of unsaturation and use it for data analysis, I think it is important to explain the underlining logics of the equation so that people can understand it, not just memorize it. Hopes this helps.
Thuy Hoang
Posted 23:33, 5 Mar 2009
Anhthu Do says:
Your module is very clear and easy to follow. Good job! What could make it better, however, is adding some real-life examples of saturated and unsaturated compounds. Personally, as a reader, I would like to know why figuring out if a compound is saturated or unsaturated is important to me. For example, we hear a lot about how "saturated fats" are bad. Why is this? From your module, we can tell that saturated fats have no double bonds, but why is being saturated with hydrogens a bad thing? These are things that would be really interesting to know.
Posted 22:34, 6 Mar 2009
Satish Balasubramanian? says:

This module is easy to follow, conveys a great deal of information without being to wordy. The method for calculating DoU was simply put, thus readily self-explanatory. You also did a good job of supplementing it with your own text. Your practice problems are good, however I would suggest adding a problem in which you ask the reader to predict a molecule based on a given molecular formula and a degree of unsaturation. Also, you may want to proofread to clear some grammatical errors (check intro for one). Overall, great page.

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