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Prepare three solutions each of NaI (aq), NaBr (aq), and NaI (aq).
The halogen has been extracted into the bottom organic phase.
1. The metallic color of iodine can be seen in both tubes in the first set of reactions.
2. The reddish color of bromine can be seen in the first test tube but not in the second.
3. The yellow color of chlorine can NOT be seen in either of the test tubes.
4. Only iodine has been extracted from the halide solutions reacted with Fe3+.
1. Cl2(aq) + 2 NaI(aq) → 2 NaCl (aq) + I2(aq)
Br2(aq) + 2 NaI(aq) → 2 NaBr(aq) + I2(aq)
2. Cl2(aq) + 2 NaBr(aq) → 2 NaCl (aq) + Br2(aq)
I2(aq) + 2 NaBr(aq) → 2 NaI(aq) + Br2(aq)
3. Br2(aq) + 2 NaCl(aq) → 2 NaBr(aq) + Cl2(aq)
I2(aq) + 2 NaCl(aq) → 2 NaI(aq) + Cl2(aq)
4. Fe3+ (aq) + NaI (aq) ---> Fe2+ (aq) + I2(aq)
X2 (aq) + 2 Y (aq) → 2 X (aq) + Y2 (aq)